Question 891689
(b)  The pmf for the poisson distribution is 
{{{p(x) = (lambda^x/x!)*e^(-lambda)}}}

{{{p(0) = (lambda^0/0!)*e^(-lambda) = 0.264}}}
==> {{{e^(-lambda) = 0.264}}} ==> {{{lambda = 1.331806176}}}
==> {{{p(1) = 1.331806176*e^(-1.331806176) = 0.352}}}, to three decimal places
Also,
{{{p(2) = (1.331806176^2/2!)*e^(-1.331806176) = 0.234}}}, to three decimal places.
==> p(x > 2) = 1 - p(0) - p(1) - p(2) = 1 - 0.264 - 0.352 - 0.234 = 0.15.