Question 891565
ab and bc are the sides of the right triangle.
You're given the hypotenuse as 7*sqrt2
{{{a^2}}} + {{{b^2}}}={{{c^2}}}
Since the sides are the same...
2{{{a^2}}}={{{c^2}}}
Let's square the hypotenuse
(7*sqrt2)^2 = 49*2, or 98
2{{{a^2}}}=98
Divide each side by 2
{{{a^2}}}=49
Take the square root of each side
a = 7
The sides are 7 and 7, and the hypotenuse is sqrt of 98 which is approximately 9.9 (9.8994949...)