Question 891461
OK, first off, simplify.
{{{x-1=(4x)/(x-2)-8/(x-2)}}}
{{{x-1=(4x-8)/(x-2)}}}
{{{x-1=4((x-2)/(x-2))}}}
{{{x-1=4}}}
{{{x=5}}}
.
.
.
OK, now the hard way. Use the common denominator {{{(x-2)}}}
{{{x((x-2)/(x-2))+8/(x-2)=(x-2)/(x-2)+(4x)/(x-2)}}}
{{{(x^2-2x)/(x-2)+8/(x-2)=(x-2+4x)/(x-2)}}}
{{{(x^2-2x+8)/(x-2)=(5x-2)/(x-2)}}}
{{{(x^2-2x+8-(5x-2))/(x-2)=0}}}
{{{(x^2-2x+8-5x+2)/(x-2)=0}}}
{{{(x^2-7x+10)/(x-2)=0}}}
{{{((x-5)(x-2))/(x-2)=0}}}
{{{x-5=0}}}
{{{x=5}}}