Question 891388
how do i find the remaining zeros of the function

h(x)=2x^4+3x^3+96x^2+147x-98;  zero: -7i
<pre>
With one root being - 7i, the factors of: 2x^4 + 3x^3 + 96x^2 + 147x - 98 are:
(x + 7i)(x - 7i)(x + 2)(2x - 1). 
Thus, besides - 7i, other roots are: {{{highlight_green(7i))}}}, {{{highlight_green(- 2))}}}, and {{{highlight_green(1/2)}}}.