Question 891320
First find the volume of one can.
{{{V[c]=pi(D/2)^2*H}}}
{{{V[c]=pi(4/2)^2*4}}}
{{{V[c]=16pi}}}
There are 12 cans so the total volume of cans is 
{{{V[tc]=12(32pi)}}}
{{{V[tc]=192pi}}}{{{cm^3}}}
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Assuming the box is 1 can high, 2 cans wide, and 6 cans deep. 
The width of the box would be {{{2D}}}.
The height of the box would be {{{H}}}.
The depth of the box would be {{{6D}}}.
So the total volume of the box would be,
{{{V[b]=2D*H*6D}}}
{{{V[b]=2(4)(4)6(4)}}}
{{{V[b]=768}}} {{{cm^3}}}
So then the difference is,
{{{V[diff]=768-192pi}}}{{{cm^3}}}