Question 891091
find the value of k that makes the sum of the roots of 3x^2-(3k+2)x+18=0 equal to 6.
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{{{3x^2 - (3k + 2)x + 18 = 0}}}

Sum of roots = {{{- b/a}}}
{{{6 = - (- (3k + 2))/3}}} ------ Substituting sum of roots value, b and a
{{{6 = (3k + 2)/3 }}}
3k + 2 = 18 ------- Cross-multiplying 
3k = 16
{{{highlight_green(highlight_green(k = 16/3))}}}