Question 891101

the frequency of vibration (f) in an open pipe organ varies inversely as the length (L) of the pipe. If the air in a pipe 2m long vibrates 60 times per minute, find the frequency in a pipe that is 1.5m long
<pre>
{{{f = k/L}}}
{{{60 = k/2}}}
k = 60(2), or 120

{{{f = k/L}}}
{{{f = 120/1.5}}}
frequency, or {{{highlight_green(highlight_green(f = 80))}}}