Question 891101
Phrased in variation language.  {{{highlight_green(f=k/L)}}} for some constant k.


{{{k=f*L}}}
Given the values for finding k,
{{{k=60*2*(cycles/sec)*(meters)}}}
{{{k=120(cycles*meters/sec)}}}


A pipe for L=1.5 has frequency {{{f=120(1.5)}}}
{{{highlight(f=180)}}} cycles per second