Question 891074

x^3 - 13x + 12 = 0<pre>
Is it that difficult to state what you want?
Assuming you want this trinomial solved, one of its roots is - 4, so x + 4 is a factor.
{{{(x^3 - 13x + 12)/(x + 4)}}} = {{{x^2 - 4x + 3}}}, and factors to: (x - 3)(x - 1)
Therefore, {{{x^3 - 13x + 12 = 0}}} becomes: {{{(x + 4)(x - 3)(x - 1) = 0}}}, so solutions or roots are: {{{highlight_green(highlight_green(x = - 4_3_and_1))}}}