Question 890939
Log arguments must be greater than zero. 
{{{x-3>0}}}
{{{x>3}}}
So as x approaches 3, f goes towards negative infinity.

So now we have a lower limit.
{{{g(4)=log((4-3))=log((1))=0}}}
{{{g(5)=log((5-3))=log((2))=.301}}}
{{{g(6)=log((5-3))=log((3))=.477}}}
{{{g(7)=log((5-3))=log((4))=.602}}}
{{{g(8)=log((8-3))=log((5))=.699}}}
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{{{drawing(300,300,-1,9,-1,2,
circle(4,0,0.2),
circle(5,0.301,0.2),
circle(6,0.477,0.2),
circle(7,0.602,0.2),
circle(8,0.699,0.2),
graph(300,300,-1,9,-1,2,ln(x-3)*.434294))}}}