<PRE><B>Question 75052</B>
Give the vertices of the hyperbola (x-12)^2/16 - (y-14)^2/25 = 1

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The center is at (12,14)
The semi-major axis is sqrt25=5 and that axis is vertical.
Vertices on the major axis are (12, 14+5)=(12,19) and (12,14-5)=(12,9)
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The semi-minor axis is sqrt16=4 and that axis is horizontal.
Vertices on the minor axis are (12+4,14)=(16,14) and (12-4,14)=(8,14)
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Cheers,
Stan H.</PRE>