Question 890778
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{i}\ =\ \left(\frac{5}{i}\right)\frac{i}{i}\ =\ \frac{5i}{i^2}\ =\ \frac{5i}{-1}\ =\ -5i]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \