Question 890699
Three numbers specified would be 2n+1, 2n+3, 2n+5.


{{{(2n+1)+(2n+3)+(2n+5)=99}}}
{{{6n+9=99}}}
{{{6n=90}}}
{{{n=90/6}}}
{{{n=(3*3*2*5)/(2*3)}}}
{{{n=15}}}


Numbers are <b>31, 33, 35</b>.