Question 890650
Eliminate negative exponents and rationalize the denominator in the final answer. 

[(3x+5)^1/3 — x/(3x+5)^2/3] / (3x+5)^2/3

I have no idea where to start on this problem. I was trying to solve the subtraction problem in the numerator but the "x" is throwing me off. This problem has rational exponents and complex fractions; both of which I have forgotten how to handle. 
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{{{((3x + 5)^(1/3) - x/((3x + 5)^(2/3)))/((3x + 5)^(2/3))}}}______{{{((3x + 5)^(1/3) - x/((3x + 5)^(2/3)))}}} ÷ {{{(3x + 5)^(2/3)}}}
{{{((3x + 5)^(1/3) * (3x + 5)^(2/3) - x)/((3x + 5)^(2/3))}}} ÷ {{{(3x + 5)^(2/3)}}}_____{{{((3x + 5)^(1/3 + 2/3) - x)/((3x + 5)^(2/3))}}} ÷ {{{(3x + 5)^(2/3)}}}______{{{((3x + 5 - x)/((3x + 5)^(2/3)))}}} ÷ {{{(3x + 5)^(2/3)}}}
{{{((2x + 5)/((3x + 5)^(2/3)))}}} ÷ {{{(3x + 5)^(2/3)}}}______{{{((2x + 5)/((3x + 5)^(2/3)))}}} * {{{1/((3x + 5)^(2/3))}}}_____{{{highlight_green(highlight_green((2x + 5)/(3x + 5)^(4/3)))}}}