Question 890446
{{{8x^2 + 4x = -1}}}
{{{8x^2 + 4x+1=0}}}
{{{8(x^2+(1/2)x+(1/16))+1=8(1/16)}}}
{{{8(x+1/4)^2+1=1/2}}}
{{{8(x+1/4)^2=-1/2}}}
{{{(x+1/4)^2=-1/16}}}
{{{x+1/4=0 +- (1/4)i}}}
{{{highlight(x=-1/4 +- (1/4)i)}}}