Question 890393
You still look for the roots but you now also decide which interval or intervals makes the inequality true.



{{{x^2-2x-3=(x+1)(x-3)>0}}}


The zeros or roots would be the critical points, making three intervals:
(-infinity, -1), (-1, 3), (-3, infinity).
Pick any value in each interval and test if satisfies the inequality.


You should find that the solutions are {{{highlight(x<-1)}}} or {{{highlight(x>3)}}}.