Question 890268
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Hint:  If they start 540 km apart and then meet 3 hours later, they traveled, in sum, 540 km in 3 hours, so the sum of their speeds is 540 divided by 3, or 180 km/hr.  So if the slow car is going x km/hr, the fast car must be going x + 12 km/hr.  x + (x + 12) = 180.  Solve for x.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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