Question 890206
It should be written, f(x)=3x-2/x^2-x-12;


{{{highlight_green(f(x)=(3x-2)/(x^2-x-12))}}}.


What do you want from it?  


The denominator is factorable.
{{{f(x)=(3x-2)/((x+3)(x-4))}}}


The function has a root (zero) at {{{x=2/3}}} and vertical asymptotes for x=-3 and x=4.  You can check intervals between the critical values to find signs in those intervals to get a better idea of the shape of the graph.


{{{graph(300,300,-12,12,-12,12,(3x-2)/(x^2-x-12))}}}