Question 890223
1. Find two consecutive whole numbers whose product is 156? 
n(n+1) = 156
n^2 + n = 156
n^2 + n - 156 = 0
Factors to
(n+13)(n-12) = 0
positive solution
n = 12, and 13 are the two numbers
:
2. The sum of a number and it's reciprocal is 25/12
n + {{{1/n)}}} = {{{25/12}}}
multiply by 12n, cancel the denominators and you have:
12n^2 + 12 = 25n
12n^2 - 25n + 12 = 0
Use the quadratic formula, leave the solutions in fractions
I got
n = {{{3/4}}}
and
n = {{{4/3}}}
Either one will work
:
 3.The area of a triangle is 135cm2. if the altitude is 1/3 the base, what are lengths of the altitude and the base?
A = {{{1/2}}}b*h
let a = the altitude, the b = 3a
{{{1/2}}}*3a*a = 135
multiply both sides by 2
3a^2 = 270
Divide both sides by 3
a^2 = 270/3
a^2 = 90
a = {{{sqrt(90)}}}
extract the square root of 9
a = {{{3sqrt(10)}}} is the altitude
and then b is 3 times that
b = {{{9sqrt(10)}}} is the base