Question 890019
n=3;
4 and 4i are zeros;
f (2)= -80
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If 4i is a zero, so is -4i
--> (x-4)*(x-4i)*(x+4i) = 0
(x-4)*(x^2+4) = 0
{{{x^3 - 4x^2 + 4x - 16 = 0}}}
f(2) = 8 - 16 + 8 - 16 = -16
-80/-16 = 5
Multiply by 5
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--> {{{5x^3 - 20x^2 + 20x - 80 = 0}}}