Question 10124
there are 3 consecutive inteters:
#1: x
#2: x+1
#3: x+2


x+{{{(1/2)(x+1)}}}+{{{(2)(x+2)-7}}}=2101
x+{{{(x/2)+(1/2)}}}+2x+4-7=2101
2(x+{{{x/2}}}+{{{1/2}}}+2x+4-7=2101)
2x+x+1+4x+8x-14=4202
15x-13=4202
15x=4215
x={{{4215/15}}}
x=281


the first number is 281. since they are consecutive numbers, the numbers are 281, 282, 283