Question 890053

A bag contains 6 cherry, 3 orange, and 2 lemon candies. You reach in and take 2 pieces of candy at random. Find the probability of both being lemon.
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P(L & L) = P(L) * P(L)
P(1st being a lemon):  {{{2/11}}}
P(2nd being a lemon):  {{{1/10}}}, considering that the first candy chosen was a lemon.
P(L & L) = {{{(2/11) * (1/10)}}}, or {{{highlight_green(highlight_green(2/110))}}}