Question 890005
<pre>
There is no way to solve an 11-degree polynomial
algebraically.  The best you could do would be to
draw the graph of its inverse by finding points
on f(x), such as 

(-1,7), then its reverse (7,-1) is a point of f<sup>-1</sup>(x).
(0,3), then its reverse (3,0) is a point of f<sup>-1</sup>(x).
(1,13), then its reverse (13,1) is a point of f<sup>-1</sup>(x).
etc., etc.

You could graph it that way.  But there is no closed algebraic
expression for f<sup>-1</sup>(x)

Edwin</pre>