Question 889213
4555.31 = 4000 * e^(5k)
divide both sides by 4000 to get:
4555.31/4000 = e^(5k)
take natural log of both sides of the equation to get:
ln(4555.31/4000) = ln(e^(5k)
since ln(e^(5k) = 5k*ln(e) = 5k*1 = 5k, you get:
ln(4555.31/4000) = 5k
divide both sides by 5 to get:
k = ln(4555.31/4000) / 5 = .0259998449
set up new equation for 10 years.
y = 4000 * e^(10k)
replace k to get:
y = 4000 * e^(10*.0259998449) to get:
y = 5187.712299

your answer are:


k = .0259998449


value after 20 years = 5187.712299