Question 889975
Assume the vertex is located at (0,0).
Another point on the parabola would be (360/2,38) or (180,38)
Using the focus form of a parabola,
{{{4fy=x^2}}}
{{{4f(38)=(180)^2}}}
{{{f=(180)^2/(4(38))}}}
{{{f=213.1}}}{{{ft}}}