Question 266343
(1+tan^2x)cot^2x=csc^2x

LHS:
(1+tan^2x)cot^2x=csc^2x
=sec^2x(cos^2x/sin^2x)
=1/cos^2x(cos^2x/sin^2x)
Cancel out the cos^2x
=1/sin^2x
=csc^2x


Therefore
LHS=RHS
csc^2x=csc^2x