Question 889947
let denominator be d and numerator be n.The fraction can be written as n/d.
Numerator is one more than denominator.
     n/d = (d+1)/d
Numerator when added by 3,the fraction increases by 1.
    (n+3)/d = (d+1+3)/d = (d+1)/d+1
            = (d+4)/d = (d+1+d)/d
            = (d+4)/d = (2d+1)/d
Cancelling d in denominator of both sides,we get
           d+4 = 2d+1
          2d-d = 4-1
             d = 3
             n = 4
The resulting fraction is 4/3.
Check: 
     (n+3)/d = (4+3)/3
             = 7/3
     n/d+1 = 4/3+1
           = (4+3)/3
           = 7/3