Question 889851
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The probability that the first candy drawn is a lemon is *[tex \LARGE \frac{2}{11}].  The probability that the second candy drawn is a lemon given that the first was a lemon is *[tex \LARGE \frac{1}{10}].  The total probability of both events is the product of the two probabilities, or *[tex \LARGE \frac{2}{110}\ =\ \frac{1}{55}].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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