Question 889824
s for length of either equal side
b for the unequal side


{{{b=-2+2(s+s)}}} and {{{2s+b=40}}}.
You have enough to solve this.


{{{b=2*2s-2}}}
{{{b=4s-2}}}
-
Substitute.
{{{2s+4s-2=40}}}
{{{6s-2=40}}}
{{{6s=42}}}
{{{s=7}}}---one part
-
{{{b=4*7-2}}}
{{{b=28-2}}}
{{{b=26}}}---other part