Question 889761
{{{tan^2(x)-sin^2(x)=sin^2(x)(1/cos^2(x)-1)}}}
{{{sin^2(x)/cos^2(x)-sin^2(x)=sin^2(x)(1/cos^2(x)-1)}}}

{{{sin^2(x)/cos^2(x)-sin^2(x)=sin^2(x)(sec^2(x)-1)}}}
{{{sin^2(x)/cos^2(x)-sin^2(x)=sin^2(x)tan^2(x)}}}
{{{sin^2(x)/cos^2(x)-sin^2(x)=tan^2(x)sin^2(x)}}}
{{{tan^2(x)-sin^2(x)=tan^2(x)sin^2(x)}}}