Question 889758
Write in vertex form.
{{{y=a(x+1)^2-108}}}
When {{{x=0}}}
{{{y=a(0+1)^2-108=-105}}}
{{{a-108=-105}}}
{{{a=3}}}
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{{{y=3(x+1)^2-108}}}
{{{3(x+1)^2=108}}}
{{{(x+1)^2=36}}}
{{{x+1=0 +- 6}}}
{{{x=-1 +- 6}}}
{{{x=-7}}} and {{{x=5}}}
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(-7,0),(5,0)