Question 889705
{{{(x - 1/x)^2=x^2-1-1+1/x^2}}}
{{{(x - 1/x)^2=x^2+1/x^2-2}}}
Similarly,
{{{(x + 1/x)^2=x^2+1/x^2+2}}}
So,
{{{(x + 1/x)^2=(x - 1/x)^2+4}}}
{{{(x + 1/x)^2=5+4}}}
{{{(x + 1/x)^2=9}}}
{{{x + 1/x=0 +- 3}}}