Question 889697

Given that x^2=y^2 - 4xz, find the value of x when y=1 and z=3/8
<pre>
{{{x^2 = y^2 - 4xz}}}
{{{x^2 = 1^2 - 4x(3/8)}}} ------ Substituting 1 for y, and {{{3/8}}} for z
{{{x^2 = 1 - 3x/2}}}
{{{2x^2 = 2 - 3x}}} ------ Multiplying by LCD, 2
{{{2x^2 + 3x - 2 = 0}}}
Solve for x
Then do a check!! 

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