Question 74884
{{{ 5^x = 4^(x+1) }}}
then {{{log 5^x=log 4^(x+1)}}}
{{{x*log 5 = (x+1)*log 4}}}
{{{x(log 5-log 4) = log 4}}}
{{{x = log 4/(log 5-log 4)}}}