<PRE><B>Question 889535</B>
How do yo find the mean and standard error of the sample mean that is normally distributed with a mean of 10 and a standard deviation of 2 when the sample size is 25?
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The Central Limit Theorem says::
The mean of the sample means = The population mean
The std of the sample means = (the std of the population)/sqrt(sample size)
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Your Problem
mean of sample means = 10
std of sample means = 2/sqrt(25) = 2/5
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Cheers,
Stan H.
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