Question 889361
{{{((x^2+6)/(x^2+4x-12))+((7x)/(x^2+7x+6))=(x^2+6)/((x+6)(x-2))+(7x)/((x+6)(x+1))}}}
{{{((x^2+6)/(x^2+4x-12))+((7x)/(x^2+7x+6))=((x^2+6)(x+1))/((x+6)(x-2)(x+1))+((7x)(x-2))/((x+6)(x+1)(x-2))}}}
{{{((x^2+6)/(x^2+4x-12))+((7x)/(x^2+7x+6))=((x^2+6)(x+1)+(7x)(x-2))/((x+6)(x+1)(x-2))}}}

{{{((x^2+6)/(x^2+4x-12))+((7x)/(x^2+7x+6))=((x^3+x^2+6x+6)+(7x^2-14x))/((x+6)(x+1)(x-2))}}}
{{{((x^2+6)/(x^2+4x-12))+((7x)/(x^2+7x+6))=highlight((x^3+8x^2-8x+6)/((x+6)(x+1)(x-2)))}}}