Question 889339
{{{N-3(1/N)=2}}}
{{{N^2-3=2N}}}
{{{N^2-2N-3=0}}}
{{{(N-3)(N+1)=0}}}
Two solutions:
{{{N-3=0}}}
{{{N=3}}}
and
{{{N+1=0}}}
{{{N=-1}}}