Question 889336
PLug in the value and see.
{{{sin((7pi)/3)=sqrt(3)/2}}}
{{{sin((7pi)/6)=-1/2}}}
{{{cos((7pi)/6)=-sqrt(3)/2}}}
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{{{sin(2x)sin(x)-cos(x)=(sqrt(3)/2)(-1/2)-(-sqrt(3)/2)}}}
{{{sin(2x)sin(x)-cos(x)=(sqrt(3)/2)(-1/2+1)}}}
{{{sin(2x)sin(x)-cos(x)=(sqrt(3)/2)(1/2)}}}
{{{sin(2x)sin(x)-cos(x)=highlight(sqrt(3)/4)}}}