Question 889315
Subsitute,
{{{(3x^2-2)^2-6x^2=4}}}
{{{9x^4-12x^2+4-6x^2=4}}}
{{{9x^4-18x^2=0}}}
{{{9x^2(x^2-2)=0}}}
Three solutions:
{{{x=0}}}
Then,
{{{y=3(0)^2-2}}}
{{{y=-2}}}
.
.
{{{x^2-2=0}}}
{{{x^2=2}}}
{{{x=0 +- sqrt(2)}}}
Then,
{{{y=3(0 +- sqrt(2))^2-2}}}
{{{y=3(2)-2}}}
{{{y=4}}}
.
.
.
({{{0}}},{{{-2}}}),({{{sqrt(2)}}},{{{4}}}),({{{-sqrt(2)}}},{{{4}}})