Question 889258
The surveyer can draw a triangle with 60 m side opposite the 46 degree angle,
the 70 m side opposite angle b,
and the unknown side C opposite of angle c.


Law of Sines allows:
{{{60/sin(46)=70/sin(b)}}};
{{{C/sin(c)=60/sin(46)}}};
{{{46+b+c=180}}} degrees.


If the surveyer only labels 70 m, 60 m, and the 46 degree angle, and does nothing more, then
he has not done enough of his job.  What he still ought to do is....
{{{sin(b)/70=sin(46)/60}}}
{{{sin(b)=(7/6)sin(46)}}}
{{{highlight(b=arcsin((7/6)sin(46)))}}}---needs computaion
-
{{{c=180-46-b}}}
{{{c=180-46-arcsin((7/6)sin(46))}}}---needs computation
and then
{{{C/sin(c)=60/sin(46)}}}
{{{highlight(C=60*sin(c)/sin(46))}}}---needs computation
-
He NEEDS to compute b, c and C.  With these finished computations, he can finish labeling the triangular field diagram.