Question 889137
Two cars travel the same distance. The first car travels at a rate of 37 mph and reaches it's [sic] destination in t hours.  The second car travels at a rate of 56 mph and reaches it's [sic] destination in 2.8 hours earlier than the first car.
How long does it take the first car to reach it's [sic] destination
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d = r*t = 37t
d = 56*(t - 2.8)
37t = 56t - 156.8
t = 156.8/19
t = 8.2526 hours
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it's = it is