Question 889143
{{{z=(kx)/y}}}
{{{3/5=(k(2))/3}}}
{{{2k=9/5}}}
{{{k=9/10}}}
.
.
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{{{z=(9x)/(10y)}}}
So then,
{{{z=(9(10))/(10(1/3))}}}
{{{z=27}}}