Question 889128
{{{2(L+W)=28}}}
{{{L+W=14}}}
.
.
{{{L*W=46}}}
Substituting from above,
{{{(14-W)W=46}}}
{{{14W-W^2=46}}}
{{{W^2-14W+46=0}}}
{{{(W^2-14W+49)+46-49=0}}}
{{{(W-7)^2-3=0}}}
{{{(W-7)^2=3}}}
{{{W-7=0 +- sqrt(3)}}}
{{{W=7 +- sqrt(3)}}}
Then,
{{{L=14-(7 +-sqrt(3))}}}
{{{L=7 +- sqrt(3)}}} <--- In this case it should be -/+ not +/- but I don't have that symbol.
So, the dimensions of the rectangle are,
{{{7+sqrt(3)}}} X {{{7-sqrt(3)}}}