Question 889067
{{{A+B+C+D=56}}}
{{{A=2B}}}
{{{C=(1/2)B}}}
{{{D=3(A+B)=3(2B+B)=3(3B)=9B}}}
Substituting,
{{{2B+B+(1/2)B+9B=56}}}
{{{(25/2)B=56}}}
{{{highlight(B=112/25)}}}
Then,
{{{A=2(112/25)}}}
{{{highlight(A=224/25)}}}
.
.
{{{C=(1/2)(112/25)}}}
{{{highlight(C=56/25)}}}
.
.
.
{{{D=3(224/25+112/25)}}}
{{{D=3(336/25)}}}
{{{highlight(D=1008/25)}}}