Question 889093
1.{{{y = x^2 + 5}}}
2.{{{6x – y = 3}}}
Substitute,
{{{6x-(x^2+5)=3}}}
{{{-x^2+6x-5=3}}}
{{{-x^2+6x-8=0}}}
{{{x^2-6x+8=0}}}
{{{(x-4)(x-2)=0}}}
Two solutions:
{{{x-4=0}}}
{{{x=4}}}
Then,
{{{y=4^2+5}}}
{{{y=16+5}}}
{{{y=21}}}
and
{{{x-2=0}}}
{{{x=2}}}
Then,
{{{y=2^2+5}}}
{{{y=4+5}}}
{{{y=9}}}
(4,21) and (2,9)