Question 888891
Let {{{x=sin(a)}}}
{{{2x^2-5x-3=0}}}
{{{(x-3)(2x+1)=0}}}
Two solutions:
{{{x-3=0}}}
{{{x=3}}}
{{{sin(a)=3}}}
Not a valid solution.
.
.
.
{{{2x+1=0}}}
{{{2x=-1}}}
{{{x=-1/2}}}
{{{sin(a)=-1/2}}}
{{{a=210}}} degrees and {{{a=330}}} degrees