Question 10105
Right, well first off, get rid of the fractions. To do this, we need to find common factors, so factorise the denominators first...


{{{(x/((x+1)(x-1))) - ((x+3)/((x)(x-1))) = -3/(x(x+1))}}}


ok, so we will mutliply all 3 terms by x(x+1)(x-1), to leave:


{{{x^2 - (x+1)(x+3) = -3(x-1)}}}
{{{x^2 - (x^2+4x+3) = -3x+3}}}
{{{x^2 - x^2 - 4x - 3 = -3x + 3}}}
-4x - 3 = -3x + 3
-x - 3 = 3
-x = 6


--> x = -6


jon