Question 888719
Since the total $3.10 ends in zero,
the number of quarters must be even.
So the number quarters could be 12, 10, 8, 6 and so forth.
If there were 12 quarters we would have $3.00 in quarters and would
need one dime to total $3.10.  But for this we would only have 13 coins.
If there were 10 quarters, we would have $2.50 in quarters we would
need 6 dimes to total $3.10.  For this situation we have a total
of 16 coins, so this must be our solution.