Question 888727
Probability of picking the first blue card is,
{{{P=3/(3+4+6)=3/13}}}
Now the number of blue cards and total cards has been reduced by 1.
The probability of picking the second blue card is,
{{{P=2/12=1/6}}}
So then the probability of picking two blue cards without replacement is then,
{{{P=(3/13)(1/6)}}}
{{{highlight(P=1/26)}}}