Question 888659
let one number be x
the other will be x+5

x^2+(x+5)^2 = 5(x/2)^2

x^2+x^2+10x+25=5x^2/4

multiply equation by 4

4x^2+4x^2+40x+100 = 5x^2

3x^2+40x+100=0

3x^2+30x+10x+100=0

3x(x+10)+10(x+10)=0

(x+10)(3x+10)=0

x=-10 OR -10/3

if x= -10
then x+5 =-5

The numbers are -10,-5

-10/3 , 5/3